Asked by Angie
The reaction b/t H2 and O2 yield water vapor and has a change of heat =-484kJ.Ho much PV work is done and what is the value of the change of E in kJ for the reaction of 0.50 mol of H2 with 0.25 mol of O2 amd atmospheric pressure of 1.00 , the volume change is -5.61.
Answers
Answered by
Tony
-483kJ
=-484kJ-[1.0atm[-5.60L]]
=-484kJ-[5.60Latm[101j/Latm]]
=-484kJ+565.5J
=-483kJ
=-484kJ-[1.0atm[-5.60L]]
=-484kJ-[5.60Latm[101j/Latm]]
=-484kJ+565.5J
=-483kJ
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