log base e^3 = 1/3 ln, so
2lnx = ln e^2
1/3 ln 343 = ln ∛343 = ln ln7
x^2 = 7
x = √7
solve the following logarithmic equation:
2lnx= log base e^3 343
1 answer
2lnx= log base e^3 343
1 answer
1 answer
1 answer
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3 answers