Asked by Susan
A protected area was stocked with 1500 deer of a certain species in 1995. The deer population in 2010 was found to be 3350 deer. Let t be the number of years after 1195. Find the deer population at t=3
Answers
Answered by
Steve
Assuming a constant % growth rate,
P(t) = 1500 e^kt
P(15) = 3350, so
1500 e^15k = 3350
k = 1/15 ln(3350/1500) = .0536
P(3) = 1500 e^(.0536*3) = 1762
P(t) = 1500 e^kt
P(15) = 3350, so
1500 e^15k = 3350
k = 1/15 ln(3350/1500) = .0536
P(3) = 1500 e^(.0536*3) = 1762
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.