Question
5 ml of water at 4 degree Celsius (density 1 g/ml) is converted to steam at 110 degree Celsius. What volume will the steam occupy when pressure is 380 Torr?
Answers
The volume of the steam can be calculated using the Ideal Gas Law:
V = nRT/P
where n is the number of moles of water, R is the ideal gas constant (0.0821 L·atm/mol·K), T is the temperature in Kelvin (283.15 K), and P is the pressure in atmospheres (0.49 atm).
Therefore, the volume of the steam is:
V = (5 ml * 1 g/ml / 18 g/mol) * 0.0821 L·atm/mol·K * 283.15 K / 0.49 atm
V = 11.7 L
V = nRT/P
where n is the number of moles of water, R is the ideal gas constant (0.0821 L·atm/mol·K), T is the temperature in Kelvin (283.15 K), and P is the pressure in atmospheres (0.49 atm).
Therefore, the volume of the steam is:
V = (5 ml * 1 g/ml / 18 g/mol) * 0.0821 L·atm/mol·K * 283.15 K / 0.49 atm
V = 11.7 L
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