The volume of the steam can be calculated using the Ideal Gas Law:
V = nRT/P
where n is the number of moles of water, R is the ideal gas constant (0.0821 L·atm/mol·K), T is the temperature in Kelvin (283.15 K), and P is the pressure in atmospheres (0.49 atm).
Therefore, the volume of the steam is:
V = (5 ml * 1 g/ml / 18 g/mol) * 0.0821 L·atm/mol·K * 283.15 K / 0.49 atm
V = 11.7 L
5 ml of water at 4 degree Celsius (density 1 g/ml) is converted to steam at 110 degree Celsius. What volume will the steam occupy when pressure is 380 Torr?
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