Sina+cosa=root over cosA

SinA =0.5 cosA=?

sinA + cosA > 1 where A is 0< A < 90 in ABC triangle

CosA/1+sinA=1-sinA/cosA I have to prove the identity each side has to b the same how would i do t...

prove that :cosA-sinA+1/cosA+sinA-1=cosecA+cotA

SinA+ cosA=17/3 find sinA-cosA

Given sinA=3/5 and cosA=5/13, find sin2x

sinA=.....+cosA

1-cosA+sinA DIVIDED BY 1+cosA+sinA

If cosA + sinA= root2 cosA Show that cosA - sinA= root2 sinA

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