Question

In a machine shop, a hydraulic lift is used to raise heavy equipment for repairs. The sys- tem has a small piston with a cross-sectional area of 0.063 m2 and a large piston with a cross-sectional area of 0.172 m2. An engine weighing 2800 N rests on the large piston.
What force must be applied to the small piston in order to lift the engine?
Answer in Newtons

Answer 1

pressureSmall=pressureLarge (pascal's principle)
forceSmall/areaSmall=forceLarge/AreaLarge

forceSmall=.063*2800/.172