Asked by M&M
In a machine shop, a hydraulic lift is used to raise heavy equipment for repairs. The sys- tem has a small piston with a cross-sectional area of 0.063 m2 and a large piston with a cross-sectional area of 0.172 m2. An engine weighing 2800 N rests on the large piston.
What force must be applied to the small piston in order to lift the engine?
Answer in Newtons
What force must be applied to the small piston in order to lift the engine?
Answer in Newtons
Answers
Answered by
bobpursley
pressureSmall=pressureLarge (pascal's principle)
forceSmall/areaSmall=forceLarge/AreaLarge
forceSmall=.063*2800/.172
forceSmall/areaSmall=forceLarge/AreaLarge
forceSmall=.063*2800/.172
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