Question
One hundred twenty grams of metal at 88 degree Celsius is poured into a 70 grams insulated cup contains 250 grams of water at 16 degree Celsius .The final temperature of the mixture is 17.5 degree C.Determine the specific heat capacity of the metal.
Answers
120 x specific heat ( 17.5 - 88) + 250 x 4.18 ( 17.5 - 16)=0
- 8460 x specific heat +1567.5 =0
specific heat:
=0.185 J/g°C
- 8460 x specific heat +1567.5 =0
specific heat:
=0.185 J/g°C
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