Asked by Anonymous
                A random sample of 400 morning shoppers showed that 130 were men. A random sample of 480 evening shoppers showed 187 to be men. Use a 5% level of significance to test for a significant difference in the proportion of morning and evening male shoppers. What is your conclusion? 
            
            
        Answers
                    Answered by
            Kuai
            
    n1= 400
x1 = 130
n2 = 480
x1 = 187
phat1 = x1/n1 = 130/400 = .325
phat2 = x2/n2 = 187/480 = .3896
pbar = (x1 + x2)/(n1+n2) = (130 +187)/(400+480) = .36
qbar = 1- pbar = .64
z = (325- .3896)/sqrt(.36*.64/400+ .36*.64/480)
z = -1.99
If p-value greater than alpha
Fail to reject Ho
If p-value less than alpha
Reject Ho
p-value = 0.047
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.