Asked by vector
11. A major-league pitcher can throw a baseball in excess of 42.4 m/s. If a ball is thrown
horizontally at this speed and acts like a projectile, how much will it drop by the time it
reaches the catcher who is 17.0 m away from the point of release?
horizontally at this speed and acts like a projectile, how much will it drop by the time it
reaches the catcher who is 17.0 m away from the point of release?
Answers
Answered by
Henry
V*t = 17 m.
42.4 * t = 17
t = 0.40 s.
d = 0.5g*t^2
g = 9.8m/s^2
42.4 * t = 17
t = 0.40 s.
d = 0.5g*t^2
g = 9.8m/s^2
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