Asked by Danny
A uniform bar 1.900 meters in length and having a cross sectional area of 11.000cm^2 is subject to a loading of 5450.000 Newtons. this load causes an extension to the bar length of 2.420mm. Calculate the stress and strain produced.
11cm = .11m
2.420mm = .02420m
length = 1.9m
Area = L * W
= 1.9m * .11m
= .209m
Stress
= load/ Area
= 5450.000N/.209m
= 26076.555Pa
ANS = 26.076555kPa
Strain
= .02420m/1.9m
ANS = .0127368
Is this done correctly? Thank you.
11cm = .11m
2.420mm = .02420m
length = 1.9m
Area = L * W
= 1.9m * .11m
= .209m
Stress
= load/ Area
= 5450.000N/.209m
= 26076.555Pa
ANS = 26.076555kPa
Strain
= .02420m/1.9m
ANS = .0127368
Is this done correctly? Thank you.
Answers
There are no human answers yet.
Answered by
Bot
Yes, your calculations are correct.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.