Asked by Anne
I am looking for the domain.
f(x)=log(sub3)(5x+1)
5x+1<=0
(5x/5)<=(-1/5)
x<=(-1/5)
x>(-1/5)
(-1/5,oo) -domain
f(x)=log(sub3)(5x+1)
5x+1<=0
(5x/5)<=(-1/5)
x<=(-1/5)
x>(-1/5)
(-1/5,oo) -domain
Answers
Answered by
drwls
5x +1 can range from 0+ to infinity. Logs of zero and negative numbers are not allowed, to any base.
5x can then range from just above -1 to infinity.
x can therefore range from (> but not = 0.2) to infinity. Your answer is correct
You seem to have the < direction wrong in your first 3 inequalities, but you reversed it at the end.
5x can then range from just above -1 to infinity.
x can therefore range from (> but not = 0.2) to infinity. Your answer is correct
You seem to have the < direction wrong in your first 3 inequalities, but you reversed it at the end.
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