Asked by Alex
Determine which pairs of lines are parallel or perpendicular.
x = 1-3t, y = 7+4t
x = 2-4s, y = -3s
L1: r = (1,7) + t(-3,4)
L2: r = (2,-3) + t(-4,-3)
Now how is that perpendicular? I know how to find it a vector of a line is parallel but I don't know how to find out if it's perpendicular.
x = 1-3t, y = 7+4t
x = 2-4s, y = -3s
L1: r = (1,7) + t(-3,4)
L2: r = (2,-3) + t(-4,-3)
Now how is that perpendicular? I know how to find it a vector of a line is parallel but I don't know how to find out if it's perpendicular.
Answers
Answered by
drwls
I assume you are talking about an x,y plot. You have to eliminate the parameters t or s to see how x and y are related.
For the first pair of lines; line 1
t = (1-x)/3
y = 7 + (4/3)(1-x) = 28/3 - (4/3)x
For the other line,
s = (2-x)/4
y = -(3/4)(2-x) = (3/4)x -3/2
Those two lines are perpendicular, because the products of their slopes is -1.
I assume the other pair of lines is parallel, but I am unfamiliar with the (r,t) representation.
For the first pair of lines; line 1
t = (1-x)/3
y = 7 + (4/3)(1-x) = 28/3 - (4/3)x
For the other line,
s = (2-x)/4
y = -(3/4)(2-x) = (3/4)x -3/2
Those two lines are perpendicular, because the products of their slopes is -1.
I assume the other pair of lines is parallel, but I am unfamiliar with the (r,t) representation.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.