Do not forget to multiply by 10^-4 when converting cm² to m²
Here we are talking about shear stress, which is dependent on the thickness and the circumference of the hole, not the area.
Surface area which resists shear force is similar to the lateral surface area of a cylinder:
As= πd *thickness
=π*3 cm * 8 cm
=24π cm²
=0.0024 m²
Shear strength, τu = 670 mPa
Load required
=As*τu
=0.0024*670*10^6 N
=1.608*10^6 N
A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch?
First find the area:
A = pi*d^2/ 2
= 3.1416 * 3cm^2/ 2
= 3.1416 * 9/ 2
= 28.2744/ 2
= 7.0686cm
Stress = 670GPa
Second, covert 679Gpa to cm.
670Gpa = 6.7e+11N/m^2
= 67000000N/cm
Stress = Load/ Area
Force = Stress * Area
= 67000000 * 7.0686
= 4,735,962.00GN
I found this a little confusing. I could use a little help solving the question. Thank you.
1 answer
1 answer