Question
What will be the final volume of a 425 mL sample of gas initially at 22 degrees C and 1 atm pressure when the temperature is changed to 30 degrees C and the pressure to 0.471 atm?
Answers
Steve
PV = kT
V = kT/P
Given new P and T, call them P' and T', we have
V' = kT'/P'
V'/V = kT'/P' * P/kT = (T'/T)(P/P')
P' = .471P
T' = (30+273)/(22+273) = 1.0271T
So, we now must have
V'/V = 1.0271/.471 = 2.18
V' = 2.18 * 425 = 927 mL
V = kT/P
Given new P and T, call them P' and T', we have
V' = kT'/P'
V'/V = kT'/P' * P/kT = (T'/T)(P/P')
P' = .471P
T' = (30+273)/(22+273) = 1.0271T
So, we now must have
V'/V = 1.0271/.471 = 2.18
V' = 2.18 * 425 = 927 mL