A volleyball is spiked so that it has an initial velocity of 12.0 m/s directed downward at an angle of 53.2 ° below the horizontal. What is the horizontal component of the ball's velocity when the opposing player fields the ball?

Answer 1

Vo = 12m/s[53.2o].
Xo = 12*cos 53.2 = 7.2 m/s.

NOTE: The hor. component remains constant during the flight.