Asked by Haime
If the total mass of the hydrogen in the hindenburg zeppelin was 18000kg, what volume did the hydrogen occupy?
Answers
Answered by
MathMate
2 grams of hydrogen occupies 22.4 litres,
so
18000kg=18000*1000 g will occupy
18000000/2*22.4 L
=9000 m³ (at STP)
so
18000kg=18000*1000 g will occupy
18000000/2*22.4 L
=9000 m³ (at STP)
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