Asked by Anonymous
A coin is at the bottom of a fountain 60 cm deep. The water in the fountain is frozen. What is the apparent depth of the coin? The index of refraction of ice is 1.31.
Answers
Answered by
Elena
n=R/A
A=R/n = 0.6/1.31=0.458 m
http://www.saburchill.com/physics/chapters3/0004.html
A=R/n = 0.6/1.31=0.458 m
http://www.saburchill.com/physics/chapters3/0004.html
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