Asked by Abi

Please help.
I'm having a lot of trouble with solving inequalities and graphing them

solve the inequality and graph the solution on the real number line

x^2+x-6/x

I got SS: -infinity to -3 including -3 union -2 to infinity including -2

is that right?

Answers

Answered by Abi
EDIT WHERE INEQUALITY IS GREATER THAN OR EQUAL TO ZERO
Answered by Damon
do you mean
6/x
or do you mean
(x^2+x-6)/x
????
Answered by Abi
Sorry i should have put that in parenthesis
(x^2+x-6)/x greater than or equal to 0
Answered by Damon
well we know that when x = 0, it is -6/0
which is undefined but is huge positive for x small negative and huge negative for x small positive, so sketch that on your graph.

for x large positive x + 1 - (6/x) looks like y = x so draw a line sloping up at 45 degrees for large positive x
for x large negative x + 1 -(6/x) looks like y = x again so sloping down at 45 degrees in quadrant 3

Now, where is it zero?
x^2 + x - 6 = 0
(x-3)(x+2) = 0
x = -2 or x + +3

well, that does it, look at your graph sketch
it is positive from x = -2 to x = 0
it is positive from x = 3 to x = +oo
Answered by Damon
(x+3)(x-2) = 0
x = -3 or x = +3
positive from x = -3 to x = 0
positive from x = +2 to x = +oo
Answered by Abi
Isn't it x^2+x-6 = 0
(x+3)(x-2) = 0?
x = -3 or x= +2?
Answered by Damon
x = 3 or x = +2 I mean
Answered by Damon
x = -3 or x = +2
Answered by Abi
I ended up with SS: (-00,-3]union [2,00)

why would it be -3 to 0?
Answered by Damon
because it is zero at -3
then when x approaches zero from the left it is like -6/-.00000001 which is big positive
Answered by Damon
for example try x = -1

y = (1 + 1 - 6)/-1
= -6/-1
= +6
Answered by Damon
I can not seem to type anything right tonight

y = (1 - 1 -6)/-1
= -6/-1
= +6
Answered by Abi
See, this is where i have trouble understanding.

if i put if in the calculator i see why it'd be -3 to 0

but in the exams the professor makes sure we are not able to graph inequality in calculator

my graph was off on paper, i just verified on ti84+ and it looks different :-/
Answered by Damon
LOL try -3/-.001
Answered by Damon
rather -6/-.001
Answered by Damon
No need for calculator
-anything over -anything is positive.
besides check when x = -1
which is between x = -3 and x = 0
Answered by Abi
Aww it's not funny, it's frustating! :(

you want me to replace x with -3

not sure what you're meaning by that try -3/-.001

where did you get the .001??

I'm so sorry i'm not understanding and thank you so much for helping
Answered by Damon
always check an easy point within the domain you are looking at.
Answered by Damon
I am saying what will happen when x = -.001 which is between x = -3 and x = 0
the answer you can see will be positive.
Answered by Damon
just about -6 / -.001
which is positive
Answered by Damon
I have not used a calculator.
Answered by Abi
yes, it gives me 6001.001 as an answer

You're not using a cal?
Answered by Abi
if i replace -.001 with x i get 6001.001

how are you solving that without calculator
Answered by Abi
but if replace x with -4 i get a positive answer too!
Answered by Damon
because if x = -.001
then
x^2 is tiny
x is tiny
-6 is -6
so we have -6/-.001 which is 6000
which is pretty much what your calculator says
Answered by Abi
I'm still not understanding...
it's okay i'll keep trying to figure it out.
im clearly not double checking it right since i checked for 1 and got a positive answer but its supposed to be negative till 2 :-/

thank you so much for your time!
it is honestly appreciated :)
Answered by Damon
if x = -4
(16 -4 -6) / -4
= 6/-4
which is negative
Answered by Damon
If x = 1
then
(1 + 1 - 6)/1
= -4/1
= -4
Answered by Damon
You are welcome
Go back over all that and I bet you get it.
Answered by Abi
:D thank you!!!
I guess I've been staring at this for too long and probably not typing them correctly on the calculator!

THANK YOU SO MUCH!!!!!!
Answered by Damon
You are welcome, good luck with it. Forget the calculator and read that all carefully.
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