Asked by Sara
Reaction of hydrazine with chlorate ions
N2H4(g) + ClO3-(aq) → NO(g) + Cl-(aq)
Balanced:
3N2H4(g) + 4ClO3-(aq) → 6NO(g) + 6H2O(l) + 4Cl-(aq)
Reducing agent: ClO3-
Oxidizing agent: N2H4
Right?
N2H4(g) + ClO3-(aq) → NO(g) + Cl-(aq)
Balanced:
3N2H4(g) + 4ClO3-(aq) → 6NO(g) + 6H2O(l) + 4Cl-(aq)
Reducing agent: ClO3-
Oxidizing agent: N2H4
Right?
Answers
Answered by
DrBob222
The equation is balanced.
You have reversed the reducing and oxidizing agents.
Oxidation is loss of e. Cl goes from +5 to -1 and that gains electrons. It must be reduced which makes it the oxidizing agent.
N goes from -4 to +4 which is loss of e which makes it oxidized and means it is the reducing agent.
You have reversed the reducing and oxidizing agents.
Oxidation is loss of e. Cl goes from +5 to -1 and that gains electrons. It must be reduced which makes it the oxidizing agent.
N goes from -4 to +4 which is loss of e which makes it oxidized and means it is the reducing agent.
Answered by
Jessica
Actually I think the oxidation state of N becomes +2, not +4
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