You can do this the long way.
PV = nRT
You know P, V, solve for n, you know R and T. I would add the two partial pressures for A and B and solve for n, then add 0.100 mole to that and recalculate P.
A 8.90-L container holds a mixture of two gases at 45 C. The partial pressures of gas A and gas B, respectively, are .294 atm and .860 atm. If .100 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?
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