Asked by Shin
Consider the helix parametrized with the vector equation
r(t)=cos t i+ sin t j + t k.
The length L of the helix between the points (1,0,0) and (1,0,6π) is equal to aπ. What is the value of a^2?
r(t)=cos t i+ sin t j + t k.
The length L of the helix between the points (1,0,0) and (1,0,6π) is equal to aπ. What is the value of a^2?
Answers
Answered by
Steve
just plug in the formula:
s = ∫√(dx^2 + dy^2 + dz^2)
= ∫[0,6π] √(sin^2t + cos^2t + 1) dt
= √2 t [0,6π]
= 6√2 π
so, a^2 = 72
s = ∫√(dx^2 + dy^2 + dz^2)
= ∫[0,6π] √(sin^2t + cos^2t + 1) dt
= √2 t [0,6π]
= 6√2 π
so, a^2 = 72
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