Asked by k
A ship is sailing due east at 18 knots runs into a 3 knot current moving 40 East of North.
The resultant speed an direction of the ship are:
The resultant speed an direction of the ship are:
Answers
Answered by
MathMate
obtained by adding the two vectors:
(18,0)+(3cos(40),3sin(40))
=(18+3cos(40), 3sin(40))
=(x,y)
The resultant speed R is obtained by
|R|=sqrt(x²+y²)
(18,0)+(3cos(40),3sin(40))
=(18+3cos(40), 3sin(40))
=(x,y)
The resultant speed R is obtained by
|R|=sqrt(x²+y²)
Answered by
alemzewud
good
Answered by
Anonymous
A ship travelling due West at 16 knots runs into a current moving at 4 knots due
South. Find the resultant and direction of the ship.
South. Find the resultant and direction of the ship.
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