Asked by linette
how do you solve for f(x)=2x if<0
x+1 if less than or equal to zero? Can you show step by step. Having trouble getting answer and graphing.
x+1 if less than or equal to zero? Can you show step by step. Having trouble getting answer and graphing.
Answers
Answered by
Steve
Don't know what you mean by "solve" here.
They have defined a function in two pieces. What do you need to do with it?
I also suspect a typo, since "x<0" and "x less than or equal to zero" are basically the same.
If you can graph y=2x then just draw the line, omitting everything right of the y-axis.
Then graph y=x+1, chopping it off at the y-axis so only the right-hand part appears.
you will see two lines, with a jump from y=0 to y=1 at x=0.
They have defined a function in two pieces. What do you need to do with it?
I also suspect a typo, since "x<0" and "x less than or equal to zero" are basically the same.
If you can graph y=2x then just draw the line, omitting everything right of the y-axis.
Then graph y=x+1, chopping it off at the y-axis so only the right-hand part appears.
you will see two lines, with a jump from y=0 to y=1 at x=0.