e^x = 1+x+x^2/2! + ...
Looks like the series is e^5
Since cos(x) = 1 - x^2/2! + ...
Looks like the series is cos(2)
By recognizing each series below as a Taylor series evaluated at a particular value of x, find the sum of each convergent series.
A) 1+5 + (5^2)/(2!)+(5^3)/(3!)+(5^4)/(4!)+...+ (5^k)/(k!)+...=
B) 1-(2^2)/(2!)+(2^4)/(4!)-(2^6)/(6!)+...+((-1)^(k)2^(2k))/((2k)!) +...=
1 answer