Consider the following table and use the formulas that are given for computing the correlation coefficient. (Give your answer correct to two decimal places.)

Question

x 1 1 0 0 0
y 7 3 5 6 6

r =
n


xy




−


x







y






n


x2





−


x



2


n


y2





−


y



2


(1)

r =
SS(xy)

SS(x) · SS(y)

(2)

This is what I done (2)(27)/5 =10.8 for ss(xy) then 2^/5=.8 for SS(x), ten (27^)/5=145.8 for SS(y), then I put 10.8 over sqrt.8 X 145.8 = 1.00