Asked by tia
What is the pH of the solution created by combining 12.00 mL of the 0.10 M base with 8.00 mL of the 0.10 M acid
base acid
NaOH HC2H3O2
base acid
NaOH HC2H3O2
Answers
Answered by
tia
correction: the base is NaOH and acid is HC2H3O2
Answered by
DrBob222
I'll let HAc stand for HC2H3O2.
Then NaOH + HAc ==> NaAc + H2O.
Calculate mols NaOH. mols = L x M = ??
Calculate mols HAc. mol = L x M = ??
They react in 1:1 ratio. Use logic to determine how much NaAc is produced and how much NaOH remains unreacted. <b> Note: Check the problem. Problems of this type USUALLY have excess acid, not base, so it makes a buffer solution. This one is not a buffer. </b>
Then NaOH + HAc ==> NaAc + H2O.
Calculate mols NaOH. mols = L x M = ??
Calculate mols HAc. mol = L x M = ??
They react in 1:1 ratio. Use logic to determine how much NaAc is produced and how much NaOH remains unreacted. <b> Note: Check the problem. Problems of this type USUALLY have excess acid, not base, so it makes a buffer solution. This one is not a buffer. </b>
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