Question
for the reaction at 20 C
NH3 (aq) + H+ (aq) <----> NH4+(aq) the equilibrium constant is calculated to be K=4.5 x 108
NH3 (aq) + H+ (aq) <----> NH4+(aq) the equilibrium constant is calculated to be K=4.5 x 108
Answers
incomplete??
thats what I have on the paper. asking to write the equilibrium epxression for this reation.
the equilibrium constant is the ratio of the concentration product of the product and the reactant of a particular reaction.
i.e. Kc = [NH4+]/[NH3][H+] where Kc is 4.5e8.
i.e. Kc = [NH4+]/[NH3][H+] where Kc is 4.5e8.
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