Asked by Anonymousab
how do you solve this can you do this with the steps do I an understand them,please.
(square root start) 4x-8 (square root end)=-8
(square root start) 4x-8 (square root end)=-8
Answers
Answered by
Reiny
√(4x-8) = -8
I can immediately tell that this equation cannot have a real number solution because the definition of √ is to give the positive square root of a number
let's see what happens when we follow our regular routine ....
square both sides:
4x-8 - 64
4x = 72
x = 18
checking:
if x = 18
LS = √(72-8) = √64 = +8
RS = -8
LS ≠ RS
there is no solution, as stated at the start
This question points out why it is important to check all resulting answers after squaring both sides of an equation.
I can immediately tell that this equation cannot have a real number solution because the definition of √ is to give the positive square root of a number
let's see what happens when we follow our regular routine ....
square both sides:
4x-8 - 64
4x = 72
x = 18
checking:
if x = 18
LS = √(72-8) = √64 = +8
RS = -8
LS ≠ RS
there is no solution, as stated at the start
This question points out why it is important to check all resulting answers after squaring both sides of an equation.
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