Asked by Andrew

A car is hauling a 89 kg trailer, to which it is connected by a spring. The spring constant is 2100 N/m. The car accelerates with an acceleration of 0.29 m/s2. By how much does the spring stretch?
Answered by Henry
F = m*a = 89 * 0.29 = 25.8 N.
d = 25.8N/2100N * 1m = 0.0123 m.
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