Buoyant force=Weight
ρ•V₁•g = Weight
V₁=x•y•z₁
ρ•x•y•z₁•g = Weight
z₁=Weight/ ρ•x•y•g =
=445/1000•4•3•9.8=0.0038 m =3.8 mm
ρ•V₁•g = Weight
V₁=x•y•z₁
ρ•x•y•z₁•g = Weight
z₁=Weight/ ρ•x•y•g =
=445/1000•4•3•9.8=0.0038 m =3.8 mm
In this case, the weight of the raft is 100 lbs (445 N), which is the same as the buoyant force acting on it in water. We can use this information to calculate the volume of water displaced by the raft.
The formula to calculate the volume of a rectangular prism (which is equivalent to the volume of water displaced) is:
Volume = length × width × height
Given:
Length = 4 meters
Width = 3 meters
Thickness = 0.6 meters
Let's calculate the volume of water displaced by the raft:
Volume = 4 meters × 3 meters × height
Now, we can set up an equation to relate the weight of the raft to the volume of water displaced:
Weight of raft = Weight of displaced water
100 lbs (445 N) = Density of water × Volume of water
Density of water is approximately 1000 kg/m^3.
Substituting the values into the equation:
100 lbs (445 N) = 1000 kg/m^3 × (4 meters × 3 meters × height)
Simplifying the equation:
445 N = 1000 kg/m^3 × (12 meters × height)
445 N = 12000 kg/m^3 × height
Now we can solve for the height:
height = 445 N / (12000 kg/m^3)
height ≈ 0.037 meters
Therefore, the height of the water line on the raft is approximately 0.037 meters.