construct your triangle in the third quadrant,
using Pythagoras, you know
r^2 = (-2)^2 + (-3)^2 = 13
r = √13
then cosØ = x/r = -2/√13 , then
sec Ø = -√13/2
Given that θ is an angle in standard position whose terminal side contains
the given point, provide the exact value of the indicated function.
(-2, -3) Find sec θ.
1 answer
1 answer