Asked by Jane
For the cell diagram
Pt(s)|H2(g)|H+(aq)||Cu2+(aq)|Cu(s)
Write a balanced equation for the half-reaction at the cathode.
The cathode is the site of reduction so copper gets reduced.
So wouldn't the answer be:
Cu2+(aq) -> Cu(s) + 2e-?
Pt(s)|H2(g)|H+(aq)||Cu2+(aq)|Cu(s)
Write a balanced equation for the half-reaction at the cathode.
The cathode is the site of reduction so copper gets reduced.
So wouldn't the answer be:
Cu2+(aq) -> Cu(s) + 2e-?
Answers
Answered by
bonjo
the cathode is the site of reduction..but you should check your equation: Note that reduction can be characterized by the gaining of electrons.
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