Asked by Anonymous
In a standard carnival game, you toss a coin on a table top marked with a grid of squares. You win if the coin lands without touching or overlapping any lines. In other words, the coin needs to land entirely inside one of the squares.
If the squares measure 1 1/2 inches across and the coin has a diameter of 1 inch, what is the probability you will win? Assume that the coin always lands on the grid
If the squares measure 1 1/2 inches across and the coin has a diameter of 1 inch, what is the probability you will win? Assume that the coin always lands on the grid
Answers
Answered by
PsyDAG
If you "assume that the coin always lands on the grid," the probability of winning is zero.
Answered by
MathMate
Assume that the "grid" means "grid of squares" is the collection of all the squares, then we consider one square:
The "safe" area for the centre of the coin is a square of 1/2"x1/2" out of a total of 1.5"x1.5".
Probability is therefore
P(win)
=.5²/1.5²
=0.25/2.25
=1/9
The "safe" area for the centre of the coin is a square of 1/2"x1/2" out of a total of 1.5"x1.5".
Probability is therefore
P(win)
=.5²/1.5²
=0.25/2.25
=1/9
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