Question

1. Find csc A, cos A and tan A of an angle A whose terminal side contains (– 12, – 5).

2. Find sin X, sec X and cot X of an angle X whose terminal side contains (– 3, 5).

Answer 1

You know that
sinØ = y/r
cosØ = x/r
tanØ = y/x
cscØ = r/y
etc

so in any point the first coordinate is the x, the 2nd is the y

1. for (-12, -5) you would be in quadrant III
x = -12, y = -5
use Pythagoras, x^2 + y^2 = r^2 ( where we keep r always positive)
we get r = 13

now simply form the ratios
sinØ = y/r = -5/13
etc

Do the same thing for #2