Asked by raja harishchandra
The complex number [2[cos(π/10)+isin(π/10)]]^5 can be written as a+bi. What is the value of a+b?
Answers
Answered by
Reiny
by De Moivre's theorem
(2( cos (π/10 + i sin (π/10) )^5
= 2^5(cos (π/2) + i sin π/2)
= 32( 0 + i(1) )
= 0 + 32i
so a = 0 , b=32
a+b = 32
(2( cos (π/10 + i sin (π/10) )^5
= 2^5(cos (π/2) + i sin π/2)
= 32( 0 + i(1) )
= 0 + 32i
so a = 0 , b=32
a+b = 32
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.