Asked by rishabh

A polynomial f(x) satisfies the equation f(x)+(x+1)3=2f(x+1). Find f(10).
that is (x+1) whole cube
Answered by MathMate
(x+1)3=2f(x+1)
Transpose the two, and switch sides
f(x+1)=(x+1)³/2
Since x+1 is the argument of the function, we replace y=x+1 and express the right-hand side in terms of y:
f(y)=y³/2
Therefore:
f(10)=10³/2
Answered by rishabh
answer is wrong
Answered by MathMate
Does
(x+1)3
stand for
(x+1)³
or
3(x+1)
?
Answered by rishabh
x+1 whole cube
but now i got the answer
thanks..
Answered by Bako
Bhosdi ke madar...points ke liye mar rha hai!!
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