Asked by Anonymous
Consider the following 6 relations on the set of real numbers:
A) y=2x−5,
B) x2+y2=1,
C) x=20−2y,
D) y=10−x2−−−−−−√,
E) y=2x2−3x+4 and
F) y=|x|
How many of these relations define y as a function of x in the domain −10≤x≤10?
A) y=2x−5,
B) x2+y2=1,
C) x=20−2y,
D) y=10−x2−−−−−−√,
E) y=2x2−3x+4 and
F) y=|x|
How many of these relations define y as a function of x in the domain −10≤x≤10?
Answers
Answered by
Reiny
A , C, and F are linear, thus defined for all x's
B)
x^2 + y^2 = 1 is a circle , thus not a function, which is only defined for -1 ≤ x ≤ +1
E) a quadratic function, defined for all x's
D) not sure what you meant here
if it is y = √(10-2x)
then it would be defined only for
10 - 2x ≥ 0
-2x ≥ -10
x ≤ 5
so no, not defined for all of -10 ≤ x ≤ 10
So all would be except B and D
B)
x^2 + y^2 = 1 is a circle , thus not a function, which is only defined for -1 ≤ x ≤ +1
E) a quadratic function, defined for all x's
D) not sure what you meant here
if it is y = √(10-2x)
then it would be defined only for
10 - 2x ≥ 0
-2x ≥ -10
x ≤ 5
so no, not defined for all of -10 ≤ x ≤ 10
So all would be except B and D
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.