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The survival rate during a risky operation for patients with no other hope of survival is 87%. What is the probability that exa...Asked by Gayle 58
The survival rate during a risky operation for patients with no other hope of survival is 87%. What is the probability that exactly four of the next five patients survive this operation? (Give your answer correct to three decimal places.)
I got 3.48
I got 3.48
Answers
Answered by
Kuai
Incorrect
p(s) =0.87
n = 5
P(x =4)
P(x) = nCx p^x(1-p)^n-x
(5C4)(0.87)^4(0.13)^1 = 0.372
p(s) =0.87
n = 5
P(x =4)
P(x) = nCx p^x(1-p)^n-x
(5C4)(0.87)^4(0.13)^1 = 0.372
Answered by
Nora 56
Thank you, I left out a complete step is how I missed it...
Answered by
Gayle 58
Sorry for the different names, there is a group of us trying to work these out together and using one computer when we have questions...
Answered by
Kuai
No problem