Let
D = {(a,b,2a): a,b all real numbers}
The set of vectors in R^3 with last entry twice the first.
E = span{(1,0,2),(2,-1,4),(0,-3,0)}
Prove that D = E
I first made an augmented matrix to find out that there is a free variable of x3. Showing that there is a solution where D is a subset of E.
How do I how that E is a subset of D?
1 answer