Asked by Duke

1200=500/x + 500/x^2 + 500/x^3 + 500/x^4

Answers

Answered by Steve
1200 = 500(1/x+1/x^2+1/x^3+1/x^4)
12/5 x^4 - x^3 - x^2 - x - 1 = 0

Now, quartics are tough to solve algebraically. Use your favorite numerical method to crack this one.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions