Asked by Anonymous
A "neon" sign contains 2.4¡Ñ10^2mL of argon. Assuming that the gas is at standard temperature and pressure, there is 1.00 moles of gas per 22.4 L of volume. How many argon atoms are present in this sign?
Answers
Answered by
bonjo
use the convention; 22.4L = 1.00moles
so convert that volume of argon in neon sign to liters and fine the mole for that volume using the above convention.
then use this; 1 mole = 6.02e23 atoms to find the number of atoms in the mole you calculated above.
so convert that volume of argon in neon sign to liters and fine the mole for that volume using the above convention.
then use this; 1 mole = 6.02e23 atoms to find the number of atoms in the mole you calculated above.
Answered by
fsdfsd
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Answered by
Johnmar Yumul
what is the answer?
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