1)A 5.0 cm real object is placed at a distance of 5.0 cm from a concave mirror of focal length 10 cm. Find the size of the image.

Question

di= -10
magnification = |di/do|
magnification = |-10/5.0|
magnification = 2

image size = (object size)*(magnification)
image size = (5.0)*(2)
image size = 10 cm (all of that is from the equation drwls gave me)

2)A rod of length 5.0 cm lies along the axis of a concave mirror of radius of curvature 20 cm. The end of the rod closer to the mirror is 15 cm from the mirror. Find the length of the image of the rod.

20/2
10 cm