Asked by pujita
                The measure of one side of a triangular field is 4.2 m .if the difference of the lengths of hypotenuse and the other side is 14 m , find the sides of the triangle and its area?
            
            
        Answers
                    Answered by
            MathMate
            
    Please check you post.  I think 4.2 m is not the right length because if you add any two sides of a triangle, it should be greater than the third side.
Here 4.2+(hypotenuse-14)=hypotenuse-9.8 which is shorter than the hypotenuse.
It probably reads 42.
Let x=length of the other side, then
x+14=hypotenuse
Apply Pythagoras theorem:
42²+x² = (x+14)²
Expand the right-hand side:
1764+x²=x²+28x+196
28x=1764-196=1568
which gives x=56
    
Here 4.2+(hypotenuse-14)=hypotenuse-9.8 which is shorter than the hypotenuse.
It probably reads 42.
Let x=length of the other side, then
x+14=hypotenuse
Apply Pythagoras theorem:
42²+x² = (x+14)²
Expand the right-hand side:
1764+x²=x²+28x+196
28x=1764-196=1568
which gives x=56
                    Answered by
            Anonymous
            
    Is it 4.2 or 42
    
                    Answered by
            Anonymous
            
    Hgjfhxtulis
    
                    Answered by
            Jenifer
            
    It is really helpful and easy to understand. Thank u so much. It made me so easy to complete my home work. It is 42 only and not 4.2 . Once again, thank you so much!!!
    
                    Answered by
            Gunmeet kaur 
            
    Yes the given data of the question was wrong 
    
                    Answered by
            Swa
            
    Not reaching at point.
    
                    Answered by
            Nandikaa
            
    really helpful..👍
    
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