Asked by Anonymous
Suppose Tori has an unfair coin which lands on Tails with probability 0.28 when flipped. If she flips the coin 10 times, find each of the following:
Question 5 options:
P(No more than 3 Tails)
P(Exactly 1 Tail)
P(At least 5 Tails)
P(Less than or equal to 2 Tails)
P(At least 1 Tail)
The standard deviation of the number of Tails
The mean number of Tails
P(Exactly 4 Tails)
P(No Tails)
P(More than 3 Tails)
1. 0.1798
2. 0.7021
3. 2.8
4. 0.1181
5. 0.1456
6. 0.0374
7. 0.9626
8. 0.2979
9. 0.4378
10. 1.42
Answers
Answered by
MathMate
Binomial distribution,
n=10
p=0.28
q=1-0.28=0.72
mean=np
variance=npq
std dev=sqrt(npq)
Exactly r successes
=P(r)
=nCr p^r q^(n-r)
Work out each of the above problems and you will find a match.
For example, the first one:
P(no more than 3 tails)
=P(0)+P(1)+P(2)+P(3)
=0.037+0.146+0.255+0.264
=0.7021 (choice #2)
etc.
Post your answers for an answer check.
n=10
p=0.28
q=1-0.28=0.72
mean=np
variance=npq
std dev=sqrt(npq)
Exactly r successes
=P(r)
=nCr p^r q^(n-r)
Work out each of the above problems and you will find a match.
For example, the first one:
P(no more than 3 tails)
=P(0)+P(1)+P(2)+P(3)
=0.037+0.146+0.255+0.264
=0.7021 (choice #2)
etc.
Post your answers for an answer check.
Answered by
Anonymous
0.9626
Answered by
Anonymous
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