Asked by Diamond

How many grams of calcium carbonate are required to prepare for 50.0 grams of calcium oxide
Answered by bobpursley
Have you considered writing the balanced equation?

CaCO3>>CaO + O2

for each mole of calcium oxide, you need that number of moles of calcium carbonate.

a. how many moles of calcium oxide it 50 grams?
b. for that number of moles of calcium carbonate, how many grams is that?
Answered by bonjo
the question is based on the decomposition of calcium carbonate through heating;

CaCO3(s) --> CaO(s) + CO2(g)

50 grams of calcium oxide is 0.893moles. the theoretical mole is 1:1 between caCO3 and CaO, so 0.893moles of CaCO3 is needed.

mass of CaCO3 = moles of CaCO3 x Molar mass of CaCO3

hope that helps...

Answered by bonjo
@ bobpursley..your equation is incorrect so i came up with this one...

Answered by bobpursley
Bonjo, you are correct, I have a wrapped right thumb, messing up my typing, the correct equation is CO2 as a product, not O2. the rest of my response is correct.
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