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If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, its height in feet after t seconds is given by
f(t)=95t−16t^2
Find the average velocity for the time period beginning when t=1 and lasting
(i) 0.5 seconds
(ii) 0.1 seconds
(iii) 0.01 seconds
(iii) 0.001 seconds
1 answer