If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, its height in feet after t seconds is given by

f(t)=95t−16t^2

Find the average velocity for the time period beginning when t=1 and lasting
(i) 0.5 seconds

(ii) 0.1 seconds

(iii) 0.01 seconds

(iii) 0.001 seconds

1 answer

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