Asked by Adam

A parallel RL circuit has a reactance of 250 W and a resistance of 125 W. The phase angle of the circuit impedance is
Answered by Elena
tanφ=X(L)/R = 250/125 = 2
φ=tan⁻¹2=63.4⁰
Answered by Adam
thanks Elena ive got the same answer. i hate it when the applied answer isn't listed

18.4°
-18.4°
26.6°
-26.6°
*None of the above