Asked by Sonal
an electron with velocity v=3x10 to the power 7 m/s describes a circular path in a uniform magnetic field of 0.2T perpendicular to it calculate the radius of the path?
Answers
Answered by
Elena
ma=F
mv²/R=qvBsinα
circular path = >sinα = 90⁰
q=e= e =1.6•10⁻¹⁹ C,
m=9.1•10⁻³¹ kg
R=mv/eB =
=9.1•10⁻³¹•3•10⁷/1.6•10⁻¹⁹•0.2 = …
mv²/R=qvBsinα
circular path = >sinα = 90⁰
q=e= e =1.6•10⁻¹⁹ C,
m=9.1•10⁻³¹ kg
R=mv/eB =
=9.1•10⁻³¹•3•10⁷/1.6•10⁻¹⁹•0.2 = …
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.