Asked by barco

For each pair of substances listed below, identify the one with the lower boiling point.

(a) Silane (SiH4) and Phosphine (PH3)
answer = silane

(b) Ammonia (NH3) and Phosphine (PH3)
answer = phosphine

(c) Lithium fluoride (LiF) and Hydrogen Fluoride (HF)
answer = HF

Answers

Answered by ssss
a- silane
b- phosphine
c- HF
Answered by DrBob222
Why don't you look up the b.p. on google? I think you've answered a wrong.
Answered by anonyms
No, it is absolutely correct.
Answered by CORRECTION
Silane pointing point = −112 °C, 161 K, -170 °F

Phosphine boiling point = -125.9°F (-87.7°C)

PHOSPHINE HAS A LOWER BOILING POINT!!!!

ARE YOU SURE THE ANSWERS ARE RIGHT?
Answered by ssss
My dear.....check the signs (-) on the values and then check the question once again......mu answers are 100% correct...and i have scored 100% n this exam also.....:P
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