Asked by Nora
Consider the following.
P(A) = 0.27 and P(B) = 0.36,
A and B are mutually exclusive events
(a) Find the probability P(A). (Give your answer correct to two decimal places.)
(b) Find the probability P(B). (Give your answer correct to two decimal places.)
(c) Find the probability P(A or B). (Give your answer correct to two decimal places.)
(d) Find the probability P(A and B). (Give your answer correct to two decimal places.)
P(A) = 0.27 and P(B) = 0.36,
A and B are mutually exclusive events
(a) Find the probability P(A). (Give your answer correct to two decimal places.)
(b) Find the probability P(B). (Give your answer correct to two decimal places.)
(c) Find the probability P(A or B). (Give your answer correct to two decimal places.)
(d) Find the probability P(A and B). (Give your answer correct to two decimal places.)
Answers
Answered by
MathMate
Hints:
P(A∪B)=P(A)+P(B)+P(A∩B)
So if any three of the four probabilities are known, we can find the fourth one.
Note:
Events A and B are mutually exclusive if and only if P(A∩B)=0.
P(A∪B)=P(A)+P(B)+P(A∩B)
So if any three of the four probabilities are known, we can find the fourth one.
Note:
Events A and B are mutually exclusive if and only if P(A∩B)=0.
Answered by
Nora
sorry this has not helped me at all....I am so confused on this stuff...
Answered by
DE
.68
There are no AI answers yet. The ability to request AI answers is coming soon!